7X+3Y^2+2Z^3=414

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Solution for 7X+3Y^2+2Z^3=414 equation: 


Simplifying
7X + 3Y2 + 2Z3 = 414

Solving
7X + 3Y2 + 2Z3 = 414

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-3Y2' to each side of the equation.
7X + 3Y2 + -3Y2 + 2Z3 = 414 + -3Y2

Combine like terms: 3Y2 + -3Y2 = 0
7X + 0 + 2Z3 = 414 + -3Y2
7X + 2Z3 = 414 + -3Y2

Add '-2Z3' to each side of the equation.
7X + 2Z3 + -2Z3 = 414 + -3Y2 + -2Z3

Combine like terms: 2Z3 + -2Z3 = 0
7X + 0 = 414 + -3Y2 + -2Z3
7X = 414 + -3Y2 + -2Z3

Divide each side by '7'.
X = 59.14285714 + -0.4285714286Y2 + -0.2857142857Z3

Simplifying
X = 59.14285714 + -0.4285714286Y2 + -0.2857142857Z3

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